regex - Replacing only first block of text between dilimiters with content of file using sed -

i have been tasked replacing license boiler plate text in large number of files. because there many i'd script it, , ideally in one-liner using sed.

i know this similar question can use like:

find . -type f -exec \     sed -i -ne '/^\/\/ dom-ignore-begin/ {p; r /path/to/new/license.txt' \     -e ':a; n; /^\/\/ dom-ignore-end/ {p; b}; ba}; p' '{}' \; 

which find files , replace between ^// dom-ignore-begin , ^// dom-ignore-end content of replacement license file. , that's fine , dandy, works charm.

the problem is, of files contain multiple dom-ignore-* blocks, new license replaces whatever in blocks - far ideal.

so i'd know how can limit replacement on first block found , skip rest. regex-fu lacking in respect.

sample input:

blah blah blah blah blah  // dom-ignore-begin foo foo foo foo // dom-ignore-end  blah blah blah blah  // dom-ignore-begin foo foo foo foo foo foo foo foo foo // dom-ignore-end  blah blah 

expected output:

blah blah blah blah blah  // dom-ignore-begin bar bar           <-  bar bar           <- changed // dom-ignore-end  blah blah blah blah  // dom-ignore-begin foo foo           <- foo foo foo foo   <- not changed foo foo foo       <- // dom-ignore-end  blah blah 

this might work (gnu sed):

sed -i -e 'x;/./{x;b};x;/dom-ignore-begin/,/dom-ignore-end/{/dom-ignore-end/!d;h;rnewlicensefile' -e 'd}' file 

this uses hold space flag prevent further processing of file.

to keep dom-ignore-begin/dom-ignore-end tags use:

sed -i -e 'x;/./{x;b};x;/dom-ignore-begin/,/dom-ignore-end/{/dom-ignore-begin/{p;rnewlicensefile' -e '};/dom-ignore-end/!d;h}' file