c - Sum and get the average of the values in the array -

sum , average of values in array, , stop ask number when sum exceeds 10,000.i need clear example of these conditions.

the language fit need example in c

my code

```

#include  <stdio.h>   int main() {     int array[10];     int i, num, negative_sum = 0, positive_sum = 0;     float total = 0.0, average;      printf ("enter value of n \n");     scanf("%d", &num);     printf("enter %d numbers (negative, positve , zero) \n", num);     (i = 0; < num; i++)     {         scanf("%d", &array[i]);     }     printf("input array elements \n");     (i = 0; < num; i++)     {         printf("%+3d\n", array[i]);     }      (i = 0; < num; i++)     {         if (array[i] < 0)         {             negative_sum = negative_sum + array[i];         }         else if (array[i] > 0)         {             positive_sum = positive_sum + array[i];         }         else if (array[i] == 0)         {             ;         }         total = total + array[i] ;     }     average = total / num;     printf("\n sum of negative numbers =  %d\n", negative_sum);     printf("sum of positive numbers =  %d\n", positive_sum);     printf("\n average of input numbers =  %.2f\n", average); } 

```

answer of question

#include  <stdio.h>      int main()  { int array[10]; int num, negative_sum = 0, positive_sum = 0,j; static int i=0; float total = 0.0, average; label: j=i; printf ("enter value of n \n"); scanf("%d", &num); printf("enter %d numbers (negative, positve , zero) \n", num); (i; < (j+num); i++) { scanf("%d", &array[i]); } i=j; printf("input array elements \n"); (i; < (j+num); i++) { printf("%d\n", array[i]); } i=j; (i; < (j+num); i++) { if (array[i] < 0) {     negative_sum = negative_sum + array[i]; } else if (array[i] > 0) {     positive_sum = positive_sum + array[i]; } else if (array[i] == 0) {     ; } total = total + (float)array[i] ; } average = total / num; printf("\n sum of negative numbers =  %d\n", negative_sum); printf("sum of positive numbers =  %d\n", positive_sum); printf("\n average of input numbers =  %.2f\n", average); if(total<10000) { printf("total less 10000 , total : %.2f\n",total);  goto label; }} 

it answer of question.program run when total exceed upto 10000.