Bash - find recursively in many directories -

i have 2 or more directories path stored in variable - output of find command:

folders="$(find /g -type d -name "jpgtest*")"

note: directory names may have spaces.

assuming there 2 directories: g/jpgtest1 , g/jpgtest2.

how search subdirectories of 2 files of form "*.a",

and remove files in form "*.b" * means: name starts same name of files extension a.

for example: found: g/jpgtest1/test1/j.a

remove: g/jpgtest1/test1/j1.b , don't remove g/jpgtest1/test1/f1.b

and on 2 directories.

a possible solution:

shopt -s globstar nullglob f in $folders/**/*.a ;    rm -f "${f%.a}"*.b done

but works 1 directory found in "folders", should change work several directories well.

edit:

any solution when it's in bash script , content of "folders" unknown , , result finding folders older 1 month:

  folders="$(find /g -maxdepth 1 -type d -atime +30)"

your problem following: suppose find jpgtest1 , jpgtest2. expression $folders/**/*.a yields:

/g/jpgtest1 /g/jpgtest2/**/*.a

which expanded using glob, finding *.a files under jpgtest2. try this:

for f in /g/**/jpgtest*/**/*.a ;

if intend use output of find input, can double for reason:

for folder in $folders;    f in $folder/**/*.a ;       rm -f "${f%.a}"*.b    done done

the drawback of breaks if folder has whitespace in it. solution read line-by-line (or use ifs, i'm showing line-by-line solution):

while read folder;    f in "$folder"/**/*.a ;       rm -f "${f%.a}"*.b    done done < <(find /g -maxdepth 1 -type d -atime +30)

ITEMscalal