How to reverse a number in Java accepted by user and add both reversed number -

i have written code reverse number in java. taking 1 character/displaying it.

import java.util.scanner; class helloworld { public static void main(string args[]) { int n,n1, reverse = 0,rev = 0; system.out.println("enter number reverse");  scanner scanner = new scanner(system.in);  system.err.println("please enter first number reverse : "); int number = scanner.nextint();  system.out.println("enter second number reverse :"); int num = scanner.nextint();  if( number >0) { reverse = reverse * 10; reverse = reverse + number%10; number = number/10;   if(num>0)   {     rev = rev * 10;     rev = rev + num%10;     num = num/10;   }   }  system.out.println("reverse of entered number "+reverse);  system.out.println("reverse of entered number "+rev); } } 

input1 -65 output displayed - 5 input2 -34 output displayed - 4

i have reverse user accpeted inputs , add reverse of both boths inputs.

you can , @user7 pointed out, use while loop , instead of if loop

while( number >0) {     reverse1 = reverse1 * 10;     reverse1 = reverse1 + number%10;     number = number/10; } while( number2 >0) {     reverse2 = reverse2 * 10;     reverse2 = reverse2 + num%10;     num = num/10; }  system.out.println(reverse1+reverse2); 

now multiple numbers

int[] numbers= numbers reversed; reversesum=0; for(int i=0;i<numbers.length;i++){     reversesum+= reverse(numbers[i]); } ...  public int reverse(int number){      while( number >0)     {         reverse = reverse * 10;         reverse = reverse + number%10;         number = number/10;     }     return reverse; } 

hope helps!

good luck!