regex - Python Regular expression: is there a symbol to search for more than one occurence of a pattern? -

i know * 0 or more, , + 1 or more, if wanted indicate 2 or more (more 1)?

for example, have

>>> y = 'u0_0, p33, avg' >>> re.findall(r'[a-za-z]+', y) ['u', 'p', 'avg'] 

but want obtain ones have 2 or more letters. in example, avg.

how do this?

y = 'u0_0, p33, avg' print re.findall(r'[a-za-z]{2,}', y)                              ^^^   

{m,n} causes resulting re match m n repetitions of preceding re, attempting match many repetitions possible. example, a{3,5} match 3 5 'a' characters. omitting m specifies lower bound of zero, , omitting n specifies infinite upper bound. example, a{4,}b match aaaab or thousand 'a' characters followed b, not aaab. comma may not omitted or modifier confused described form.